carbon monoxide detector 400 ppm image
kalashniko
i bought a new digital carbon monoxide detector...it has readings up to 400( not sure what the units of measurement are) it records a week's worth of c0 levels...i had it for a couple of days and decided to check it and it said the highest reading of c0 so far was 131....but it didnt go off....so im assuming that that is still a safe/inhabitable area.....the question is....what is a dangerous level of c0 and who do i call to service my gasboiler/ gas heater cause those are the only things in my house that are powered by gas....do i call my gas guy? or my heating/cooling guy? thanks in advance
Answer
Carbon monoxide is measured in parts per million (ppm). Any CO levels higher than 10-20 should be alarming. Especially inside of a residence. If it recorded a CO level of 131 and didn't alarm, then you might want to look into getting a new detector. If you were home at the time the level was 131, you would be dead within a few hours. The signs/symptoms of acute (new onset) CO poisoning start out as headache, reddening of face, dizziness, and progress to nausea, vomiting, trouble walking and soon thereafter, unconsciousness and death. So yes, get a hold of a professional about your furnace, washer/dryer, or whatever your think the CO source may be. Hope this helps.
Carbon monoxide is measured in parts per million (ppm). Any CO levels higher than 10-20 should be alarming. Especially inside of a residence. If it recorded a CO level of 131 and didn't alarm, then you might want to look into getting a new detector. If you were home at the time the level was 131, you would be dead within a few hours. The signs/symptoms of acute (new onset) CO poisoning start out as headache, reddening of face, dizziness, and progress to nausea, vomiting, trouble walking and soon thereafter, unconsciousness and death. So yes, get a hold of a professional about your furnace, washer/dryer, or whatever your think the CO source may be. Hope this helps.
AP Chemistry homework help!!?
Faith
OK, so I did several problems, but there are slight differences when comparing my answers to the book answers. Can someone please find the mistakes.
1. A baby was born who weighs 3.91 kg and measures 51.4 cm. Convert the weight to pounds and ounces and her length to inches.
My answer: 8.62 lbs, 138 oz, and 20.2 in.
Book answer: 8lbs, 9.9oz, and 20.5 in.
2. The world record for the hundred meter dash is 9.74s. At this speed, how long would it take to run 1.00 x 10^2 yards?
My answer: 8.91 sec
I don't have the book answer for this problem, but an online answer states that it is 8.85 sec (100/11.3) where did the 11.3 come from?
Carbon Monoxide (CO) detectors sound an alarm when peak levels of carbon monoxide reach 100 parts per million(ppm). This level roughly corresponds to a composition of air that contains 400,000 micro grams carbon monoxide per cubic meter of air. Assuming the dimensions of a room at 18ft x 12ft x 8ft, estimate the mass of carbon monoxide in the room that would register 100ppm on a carbon monoxide detector.
My answer : 1.98 x 10^7 ug
Is my answer correct? If so, does that mean I complete ignore the 100 ppm when doing calculations?
Thank you!
Answer
1
As far as question 1 is concerned, I think you misunderstood what they were asking. The question wants you to take the weight in kg and convert it to a COMBINATION of pounds and ounces. In other words, they want the pounds as a whole number - and the fractional portion (.62) in ounces.
You converted kg to lb correctly 3.91 kg = 8.62 lbs ... or 8 lbs and (.62) x 16oz/lb = 9.92 oz. Instead, you gave the answer as a decimal and then converted that number (8.62) to ounces (138 oz).
Converting cm to in ... 1 cm = .3937 in
51.4 cm x .3937 in/cm = 20.2 in
#2
The question is asking: If a runner runs 100m in 9.74s, how fast can he/she run 100 yds ?
First convert 100 yards to meters ...
100 yds x .9144 m/yd = 91.44 m
So ... if a runner can run 100m in 9.74s, how long will it take the same runner to run 91.44m (100 yds) ?
Set up a ratio and solve for x.
100m /9.74s = 91.44m/x s
100x = 890.62
x = 8.906 = 8.91s
Looks like I agree with you, lol !!
Even if you look at it another way ...
100m in 9.74s = 10.266 m/s
91.44m x 1 sec/10.266m = 8.907s
(I think we're right and your online source is wrong, lol).
#3
First I calculated the area of the room (in ft^3) then I converted that to m^3 (cubic meters)
(18)(12)(8) = 1728 ft^3
1 m^3 = 35.314 ft^3
1728 ft^3 x 1 m^3/35.314 ft^3 = 48.93 m^3
The alarm sounds when the air composition reaches 400,000 micrograms/m^3 = .0004g/m^3
Multiply the area of the room in cubic meters by the alarm rate in g/m^3
48.93 m^3 x .0004 g/m^3 = .019572 g/m^3 = 19,572 micrograms
See how that matches up with other answers - good luck !!
1
As far as question 1 is concerned, I think you misunderstood what they were asking. The question wants you to take the weight in kg and convert it to a COMBINATION of pounds and ounces. In other words, they want the pounds as a whole number - and the fractional portion (.62) in ounces.
You converted kg to lb correctly 3.91 kg = 8.62 lbs ... or 8 lbs and (.62) x 16oz/lb = 9.92 oz. Instead, you gave the answer as a decimal and then converted that number (8.62) to ounces (138 oz).
Converting cm to in ... 1 cm = .3937 in
51.4 cm x .3937 in/cm = 20.2 in
#2
The question is asking: If a runner runs 100m in 9.74s, how fast can he/she run 100 yds ?
First convert 100 yards to meters ...
100 yds x .9144 m/yd = 91.44 m
So ... if a runner can run 100m in 9.74s, how long will it take the same runner to run 91.44m (100 yds) ?
Set up a ratio and solve for x.
100m /9.74s = 91.44m/x s
100x = 890.62
x = 8.906 = 8.91s
Looks like I agree with you, lol !!
Even if you look at it another way ...
100m in 9.74s = 10.266 m/s
91.44m x 1 sec/10.266m = 8.907s
(I think we're right and your online source is wrong, lol).
#3
First I calculated the area of the room (in ft^3) then I converted that to m^3 (cubic meters)
(18)(12)(8) = 1728 ft^3
1 m^3 = 35.314 ft^3
1728 ft^3 x 1 m^3/35.314 ft^3 = 48.93 m^3
The alarm sounds when the air composition reaches 400,000 micrograms/m^3 = .0004g/m^3
Multiply the area of the room in cubic meters by the alarm rate in g/m^3
48.93 m^3 x .0004 g/m^3 = .019572 g/m^3 = 19,572 micrograms
See how that matches up with other answers - good luck !!
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